![]() ![]() Then the second clock will update according to the duration. To show the actual time on clock one turn on the real time control, if the clocks are linked On the second hidden clock, which then can be revealed. The students can try to work out what the time is Press the random button, clock 1 will now ![]() Tandem with hiding parts of the interface, so for example set the Second clock will change according to the duration. ![]() The difference or duration between the two clocks is set to zero and Now if you change one clock the other will Now click the link toggle button, when on You can alsoĬontrols and manually change the values and the second clock will You drag, the minutes and hours durations change too. When the activity starts both clocks display 9am. Represents a start time, while the right clock represents an end time. Two large face clocks can show independent times the left clock Click 24 button to change to theĢ4 hour format. Click the 12 button to display in normal 12 hour format You can change the format of the digital clocks. The two digital clocks match the analogue clocks below. Problem questions at varying levels of difficulty. Using two clocks it is easier to explain time differencesīetween a start time to an end time. The two clock activity is a follow up to the clockĪctivity. Also: always use always_ff or always_comb, never use always.Two Clocks - Interactive activity to compare times Introduction This must also be added to your property. The reset can be synchronous or asynchronous as you choose. That is, both x and temp should have resets local to their individual clock domains. The flipflops created should have resets. If the above doesn't work, or if it seems like a waste to start parallel assertions checking the same thing, the following code might work.Įdit2: Put x inside property and changed two final lines in property to update x to correct values. Thus you cannot check the value made by some other instance of this assertion. I removed the out = x ^ x check from line #3 because x is local to the property. Thus t will be updated to the new value on every posedge of clkA and you will have n assertions checking the same thing(which isn't a problem). A possible fix might be to declare the variable t outside the property scope. I must admit that I am hazy on the scoping of values local to a property, but check if this is causing you troubles. Lastly, what happens if clkA is much faster than clkB? Several assertions will start in parallel and disagree on the actual value of t on the first posedge of clkB. In that case the following would be more correct, although the previous code might still work. The way I read this the assertion should start on every clkA, and then a sequence will always follow. Line #2 is not e prerequisite for line #3, and the same can be said for line #3 and line #4. In my experience a non-overlapping implication will cause the assertion to sample not on the next clkB, but skip one clkB and then sample on clkB.įurthermore I don't quite understand why you are using implications all the way through your assertion. That is, with a overlapping implication in the clock handover.
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